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y= -4x-1y2 = (-4x-1)2 = 16x2 +8x +1y2 +5x2 +2x = 0lets substitute what we found y2 equal to earlier, which gives us(16x2...
To solve this we must use integration by parts: int(udv) = uv - int(vdu) (1) Hence let u = ln(x), dv = dx => du=(1/x)dx, v=x, and now using (1) and substituting values we obtain int(ln(x)dx) = ln(x)x -...
Integration can be viewed in many ways. The most common way to interpret an integral is to take the area under the curve you would like to integrate. For example Draw y=x, limit between 0 and 1, shade...
Equation 1) x2 + y2 = 25 Equation 2) y - 3x = 13 First you need to substitute a variable so there is only one unknown in the equation: 2) y = 13 + 3x Substituting this into equation ...
To integrate this we need to use the chain rule, substituting cos2x = u Integral becomes: u2sin32x dxChain rule: dy/dx = du/dx dy/du du/dx = -2sin2x --> dx = -1/2sin2x du Substitu...
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