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As you begin the question, it is important to note that immediately multiplying the two fractions, while would eventually get you to the correct answer would take far too long in an exam scenario. Instead...
Start by modifying the first equation and making a third x=2y+1x2 = (2y+1)2 x2=4y2+4y+1therefore, if we sub this 3rd equation into the 2nd equation we get :4yAPAnswered by Adamya P. • Maths tutor6575 Views
g = b+8g+b = p = 2b+1(b/p) x (b-1)/(p-1) = 1/5(b^2 - b)/(p^2 - p) = 1/5sub in p= 2b+1(b^2 - b)/(4b^2 + 2b) = 1/55b^2 - 5b = 4b^2 + 2bb^2 -7b = 0b = 7 or b = 0 (cannot be 0 as 2 pens must be taken)p = 2(7)...
1/27 (1/3 x 1/3 x 1/3)
5 and 2/3
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