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To solve such equations we take advantage of log lawes to simplify the problem .

E.g

ln[sqrt(1-x²)] = ln[(1-x²)^1/2] = 1/2ln[1-x²]

After sim...

I would start off by asking them if they know the Pythagoras theorem. If they don't, I would refresh their memory and explain that its a²+b²=c² where...

Start by multiplying equation (2) by 4 so both equations contain 4 lots of x: 4x - 12y = 20 Then take away equation 1 from equation 2 to eliminate x -13y = 13 divide by 13 and then reverse the negative si...

To solve this you need to integrate by substitution. You can spot this because the differential of the bottom of the fraction is a multiple of the top part, showing this quickly; if u = x²  + 3...

The equation we use to integrate by parts is

y = uv - ∫ v(du/dx) dx + c

so we separate dy/dx into u=(3x-4) and dv/dx=(2x²+5)

however we still need to find du/dx an...