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To find the derivative of this, we must differentiate each term with respect to x. This implies d/dx(y^3+2xy+x^2-5=0). We can differentiate each term seperately so d/dx(y^3+2xy+x^2-5=0) is equal to d/dx(y...

new amount = old amount * (1 + interest)^(number of times interest has occured)

new amount = 1.50 * (1 + 0.03)^5 = £1.74 (rounded to 2 decimal places)

To differentiate you bring the power down and multiply it by any coefficients (numbers in front of the xs) then subtract one from the power 

So x³ becomes 3x² 

2x^2...

GHIJKLM

Use integration by parts. Let u = x^4 and let dv/dx = -sin(x). Find du/dx = 4x^3 and fin v = cos(x). Use the equation uv - int (v du/dx) = x^4 cos(x) - 4((x^4/4)*(sin(x)) = x^4 cos(x) - x^4 sin(x) = x^4 (...