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This question usually comes up at AS level where students have prior knowledge of quadratic functions:We need to 1) understand the 'shape' 2) locate the roots 3) Find the turning point 4) sketch the graph...

To answer this question, create the least common denominator possible. In this instance, the LCD is 40. (I know this because multiples of 5 only end in 0 and 5, and 40 is the lowest multiple of 8 that mee...

let x1 = 0, y1 = 0 in (0,0) and let x2 = 8 and y2 = 8 in (8,8). To find the gradient, we would do (y2 - y1)/(x2-x1) = 1. To find the length, we would do the square root of the following: (y2-y1)^2 + (y2-y...

The first thing I would do is sketch a diagram of a triangle and a pentagon. I find that tutees learn best when they can see what's going on so this makes the explanation easier to understand. After havin...

y = 1/2x^3 - 9x^3/2 + 8/x + 30y = 1/2x^3 - 9x^3/2 + 8x-1 + 30dy/dx = 3/2x^2 - 27/2x^1/2 - 8x^-2 + 0dy/dx = 3/2x^2 - 27/2x^1/2 - 8/x^2substitute x=4 into equation for yy = 1/2(4)^3 - 9(4)^3 + 8/4 +30y = 32...