Find the gradient, length and midpoint of the line between (0,0) and (8,8).

let x1 = 0, y1 = 0 in (0,0) and let x2 = 8 and y2 = 8 in (8,8). To find the gradient, we would do (y2 - y1)/(x2-x1) = 1. To find the length, we would do the square root of the following: (y2-y1)^2 + (y2-y1)^2 which gives us the square root of 128 and this simplifies to 8sqrt(2). For the midpoint, we would do ((x1+x2)/2,(y1+y2)/2) which gives (4,4).The reason why I have opted to use x1, x2, y1 and y2 is to generalise it for any numbers we are given.

Answered by Jason A. Maths tutor

2975 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that (2x + 11 )/(2x + 1)(x + 3) ≡ A /(2x + 1) + B /(x + 3) , find the values of the constants A and B. Hence show that the integral from 0 to 2 (2x + 11)/ (2x + 1)(x + 3) dx = ln 15.


What is a limit?


Find an expression in terms of powers of cos(x) for cos(5x)


Let f(x)= x^3 -9x^2 -81x + 12. Calculate f'(x) and f''(x). Use f'(x) to calculate the x-values of the stationary points of this function.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy