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A curve has parametric equations: x=(t-1)^3 and y= 3t - 8/(t^2). Find dy/dx in terms of t. Then find the equation of the normal at the point on the curve where t=2.

dx/dt = 3(t-1)2dy/dt = 3 + 16t-3dy/dx=(dy/dt)(dt/dx) dy/dx = 3 + 16t-3 / 3(t-1)2
At t=2 dy/dx= (3 + 16/8) / 3 = 5/3 Gradient of the normal = -3/5with t=2 y...

JH
Answered by Jasmin H. Maths tutor
3379 Views

How can functions be transformed?

A function, y = f(x), with y on the vertical axis and x on the horizontal axis, can be transformed by 3 different ways: It can be stretched (or shrunk)If y = f(ax), the function is stretc...

JM
Answered by Jack M. Maths tutor
2845 Views

If y = 15 + 5(x + 2), and x = 6, what is y?

Because we're told that x = 6, we can just rewrite the original equation but replace the x with a 6. So:
y = 15 + 5(6 + 2)
6 + 2 = 8, so we can rewrite this again as:
y = 15 + 5(8)
5(8...

AH
Answered by Alfie H. Maths tutor
1968 Views

How do I solve simultaneous equations like 2x + 5y = 50 and 3x + y = 23?

With simultaneous equations like these, you first want to get to a point where you have one equation with only one variable. To do this, you must eliminate one of the variables. In this case, if you multi...

AH
Answered by Alfie H. Maths tutor
1810 Views

How do I solve a quadratic equation like x^2 - 2x - 35 = 0 without using a calculator?

If possible, you should try to factorise a quadratic. To do this, look a the factors of the constant, in this case -35. 35 is clearly divisible by 5, and 35 / 5 = 7, so 5 and 7 are one pair of factors. Th...

AH
Answered by Alfie H. Maths tutor
3299 Views

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