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(i) To find the gradient of a straight light, we take any two (different) points on the straight line and compute the change in Y divided by the change in X. So here this is; (21-3)/(9-0) = 18/9 = 2. So t...
= x(1-4x^2)From difference of two squares method,= x(1-2x)(1+2x)
Start by selecting a variable to eliminate from the equations. --> Select x in this case.Take the second equation and multiply by 2. --> 2x + 6y = 38Subtract the first equation from this answer. --&...
First, we notice how there is only an 'x2' term and a number in this expression. Also notice that the number, 9, is a square number. Whenever you have an expression that looks like 'x2RAAnswered by Rebecca A. • Maths tutor22074 Views
Initially we have two unknown variables, so we want to eliminate one of the variables (x) to solve for the other (y). The LCM of 6 and 4 is 12, so multiply each equation such that the coefficient of x is ...
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