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equation of tangent is y - y1 = m(x-x1). differentiating y gives us the value of m. so dy/dx = 4x-10. we know x is 3. therefore, dy/dx = m = 2 but we need equation of the normal, which is y-y1=(1/m)(x-x1)...

Student should use a combination of trigonometric identities, product rule and chain rule to find dy/dx.This can be done by applying product rule, obtainingdy/dx = sin(2x). d[cos(x)^2]/dx + cos(x)^2. d[si...

I would convert the sin squared theta into a cos squared theta using identity that sin sq + cos sq = 1This would then give me a quadratic equation which I would substitute X = cos thetaThen I would solve ...

125^-2/3= 1/125^2/3=1/(cube root(125))^2=1/5^2=1/25

A)1) Draw a diagram of the circle displaying the centre and perimeter points along with their respective co-ordinates.2) Write down the equation for a circle labelling the centre and perimeter points. 3) ...