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Differentiate (x^2)cos(3x) with respect to x

First we start off by seeing that we are multiplying together two functions both containing x, so we want to apply the product rule. As we know the product rule is (f(x)g(x))'=f(x)g'(x)+f'(x)g(x) so we ca...

AB
Answered by Arthur B. Maths tutor
8950 Views

Write (3 + 2√5)/(7 + 3√5) in the form a + b√5

First multiply top and bottom by conjugate of denominator, (7-3√5), and expand(3 + 2√5)(7 - 3√5)/(7 + 3√5)(7 - 3√5)(21 + 14√5 - 9√5 - 30)/(49 + 3√5 - 3√5 - 45)Simplify top and botton(-9 + 5√5)/4Write in r...

BA
Answered by Beth A. Maths tutor
5797 Views

Expand using binomial expansion (1+6x)^3

(1+6x)^3 = 1+3(6x) +(3)(2)(36x^2)/2 + (3)(2)(1)(216x^3)/6
= 1+18x+108x^2 + 216x^3

OO
Answered by Ola O. Maths tutor
4244 Views

Determine the next two terms in this sequence: 2, 7, 9, 16, 25, ... , ...

In this sequence, there is no common difference between one term and the next making it more challenging to solve. However, if you look at the terms closely, you can see that each term is the sum of the p...

EW
Answered by Eleanor W. Maths tutor
12616 Views

Find the gradient at the point (0, ln 2) on the curve with equation e^2y = 5 − e^−x

Question is asking for gradient at x = 0, y = ln2. e^2y = 5 - e^-x. Differentiation with respect to x: 2e^2y * dy/dx = e^-x . dy/dx = e^-x / 2e^2y. At x = 0, y = ln2 ~ dy/dx = e^0 / 2e^2ln2 = 1 / 2e^ln4 =...

LK
Answered by Lokmane K. Maths tutor
5347 Views

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