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The equation of the line L1 is y = 3x – 2 The equation of the line L2 is 3y – 9x + 5 = 0 Show that these two lines are parallel.

In this question, you are being asked to show L1 and L2 are parallel. The equations of two parallel lines will have the same gradient. This is the number in front of the x term in the equation, but to com...

AW
Answered by Abigail W. Maths tutor
4724 Views

log3 (9y + b) – log3 (2y – b) = 2, Find y in terms of b.

Use laws of logarithms to simplify.Log3((9y+b)/(2y-b)) = 2(9y+b)/(2y-b) = 32(9y+b) = 9(2y-b)9y+b = 18y-9bCollect terms.9y = 10by = 10b/9

RA
Answered by Roy A. Maths tutor
8907 Views

Expand and simplify (3a+b)(a-2b).

To expand, you would multiply each term in the first bracket set by each term of the second bracket set. Thus, your expansion would mean:3a^2 -6ab + ab -2b^2
To simplify, note that there are two 'ab'...

HR
Answered by Hansika R. Maths tutor
10182 Views

The tangent to a point P (p, pi/2) on the curve x=(4y-sin2y)^2 hits the y axis at point A, find the coordinates of this point.

p=4pi2 differentiating with respect to y we have dx/dy = 2(4y-sin2y)(4-2cos2y) substituting in the value of y =pi/2 we have dx/dy = 24pi, which means dy/dx =1/pi24using (y-y_1)=m(x-x_1) we have...

GN
Answered by George N. Maths tutor
3692 Views

The parametric equations of a curve are: x = cos2θ y = sinθcosθ. Find the cartesian form of the equation.

x = cos2θ  y = sinθcosθcos2θ = cos2 θ  - sin2θ cos2 θ  + sin2θ  = 12cos2 θ  = 1 + cos2θ cos2 θ  = 1/2(1 + x)2sin2θ  = 1 - cos...

AN
Answered by Amelia N. Maths tutor
8396 Views

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