By completing the square, find the coordinates of the turning point of the curve with equation y = x^2 + 10x + 2

The equation is in the form ax^2 + bx + c, where a = 1, b = 10 and c = 2To complete the square, we write (x + b/2a)^2 + c - (b/2a)^2So here we would have (x + 5)^2 + 2 - 25Therefore completed square form is (x + 5)^2 - 23The turning point of this curve is therefore (-5, -23)

NM
Answered by Niamh M. Maths tutor

8033 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

This is a sequence: 2,4,7,11,16. Find the Nth term


(2x+3)/(x-4) - (2x-8)/(2x+1) = 1 Solve for x


The graph of y = x^2 – 1 is translated 3 units to the left to give graph A.The equation of graphA can be written in the form y=x^2 +bx+c Work out the values of b and c.


Refer to question taken from Edexcel Maths Paper


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning