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How do I draw a graph, y = mx + c, if I am only given m and a point that the line passes through?

Let's say we have the equation y = 2x + c and we are told that the line passes through the point (3, 4).  Our first step is to use the numbers from the point (3, 4), by substituting them into our equation...

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Answered by Alex D. Maths tutor
2840 Views

a x 10^4 + a x 10^2 = 24 240 where a is a number. Work out a x 10^4 - a x10^2 Give your answer in standard form.

From first principles: ax10^4 is the same as a0000. ax10^2 is the same as a00

So, a0000

          a00

     a0a00

If we look at this pattern and compare to the number in ...

JB
Answered by Joe B. Maths tutor
11781 Views

Express 1/((x^2)(1-3x) in partial fractions.

This is a step above a partial fraction question seen in core 1 and core 2, made mkre difficult due to the double (repeated) root of x. To solve this we must consider that there is 3 separate roots, x, x^...

JA
Answered by Jack A. Maths tutor
8744 Views

Solve the following simultaneous equations: 4x+y=10 and 2x-3y=19

To begin to solve this question, we need to re-arrange the equations presented so they both appear in terms of 3y=. This will allow us to get a value for y and thus a value for x. First re-arrange the fir...

HW
Answered by Hugh W. Maths tutor
9291 Views

Solve this pair of simultaneous equations. 5x + 2y = 20 x + 4y= 13

One way to solve simultaneous equations is to express x in terms of y (or vice versa) and solve your new equation to find one of the values. You can then substitute this into your equation to work out the...

NB
Answered by Ned B. Maths tutor
3922 Views

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