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Show that 6sin(60◦) + 5tan(60◦) can be written in the form √k where k is an integer.

sin(60◦) = √3 /2 

tan(60◦) = √3

6sin(60◦) + 5tan(60◦) = 3√3 + 5√3 = 8√3 = √64√3 = √192

AG
Answered by Alistair G. Maths tutor
3736 Views

Find all solutions to the equation 8sin^2(theta) - 4 = 0 in the interval 2(pi) < (theta) < 4(pi)

First substiute sin(theta) = x (This step is not nesecessary but often people find quadratics easier to solve in variables that they usually use). Then due to the fact that the "b" coefficient i...

NB
Answered by Nicholas B. Maths tutor
6160 Views

How can I find the derivative of y = tan(x)?

Let's first recall the definition of tan(x) = sin(x)/cos(x). Hence, y' = d/dx( sin(x)/cos(x) ). Recall quotient rule for differentiation: ( f(x)/g(x) )' = ( f '(x)^2*g(x) - f(x)*g'(x)^2 ) / g(x)^2 and tha...

RB
Answered by Riccardo B. Maths tutor
4990 Views

Solve the following equations x^2-2x+4=0, x^2+4x+1=0

x2-2x+4= (x-2)(x-2)=0  x=-2 (double root)  

x2+5x+1=0

x1,2= -5+_ (52-4(1)(1) )0.5/2 

x1=4.8     x2=-0.2 (t...

KF
Answered by Kyriakos F. Maths tutor
2957 Views

y = 4x / (x^2 + 5). Find dy/dx.

We use the quotient rule here which states that if y = f(x)/g(x) then dy/dx = (f'(x)g(x) - g'(x)f(x)) / (g(x)^2). Here f(x) = 4x and g(x) = x^2 + 5, so we have f'(x) = 4 , g'(x) = 2x. This gives us dy/dx ...

PS
Answered by Patrick S. Maths tutor
9839 Views

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