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How can I find the derivative of y = tan(x)?

Let's first recall the definition of tan(x) = sin(x)/cos(x). Hence, y' = d/dx( sin(x)/cos(x) ). Recall quotient rule for differentiation: ( f(x)/g(x) )' = ( f '(x)^2*g(x) - f(x)*g'(x)^2 ) / g(x)^2 and tha...

RB
Answered by Riccardo B. Maths tutor
5090 Views

Solve the following equations x^2-2x+4=0, x^2+4x+1=0

x2-2x+4= (x-2)(x-2)=0  x=-2 (double root)  

x2+5x+1=0

x1,2= -5+_ (52-4(1)(1) )0.5/2 

x1=4.8     x2=-0.2 (t...

KF
Answered by Kyriakos F. Maths tutor
3022 Views

y = 4x / (x^2 + 5). Find dy/dx.

We use the quotient rule here which states that if y = f(x)/g(x) then dy/dx = (f'(x)g(x) - g'(x)f(x)) / (g(x)^2). Here f(x) = 4x and g(x) = x^2 + 5, so we have f'(x) = 4 , g'(x) = 2x. This gives us dy/dx ...

PS
Answered by Patrick S. Maths tutor
10000 Views

Find the values of k for which the equation (2k-3)x^2-kx+(k-1) has equal roots

We know that an equation has equal roots if the sqrt(b^2-4ac) term in the quadratic equation is equal to zero. Therefore using this information we can form an expression for k to be (-k)^2-4(2k-3)(k-1)=0....

EH
Answered by Eliott H. Maths tutor
11941 Views

Earth is being added to a pile so that, when the height of the pile is h metres, its volume is V cubic metres, where V = (h6 + 16) 1 2 − 4.Find the value of dV/dh when h = 2.

As V=(h6+16)1/2 -4, the chain rule can be used to calculate dV/dh.

dV/dh=3h5(h6+16)-1/2

h=2 can be su...

LK
Answered by Lewis K. Maths tutor
5855 Views

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