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Notice that (sin(x))'= cos(x) and (x^2)' = 2x
We use the product rule to differentiate, by noticing the expression is a product.
so (fxgx)' = f'xgx + fx*g'x
substituting in ...
Factorise 2x2-4x-6=0
2(x2-2-3)=0 -> 2(x+1)(x-3)=0
split factors up 2=0 , (x+1)=0 and (x-3)=0
x+1=0 ->...
Substitute y into 4y-2=3x
4(2x-7)-2=3x -> 8x-28-2=3x -> 8x-3x=28+2 -> 5x=30 -> x=30/5 -> x=6
subsitute x into y=2x-7
y=2(6)-7 -> ...
Let the quadratic equation be of the form: ax2 + bx + c = 0.
Now by completing the square ( which can be done numeorous ways) get: a(x - b / 2a)2 - a(b / 2a)2 + c =...
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