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Differentiate x^2 + xy + y^2 =1 implicitly.

Each part can be done separately, so x^2 becomes 2x, xy becomes dy/dx + y by product rule, y^2 becomes 2y(dy/dx) by chain rule, and 1 becomes 0. Hence the answer is 2x + y + (2y+1)dy/dx = 0, but the answe...

TD
Answered by Tutor80806 D. Maths tutor
4349 Views

6y+2x^2=6 x=(y+1)^0.5 solve the simultaneous equations

x^2=y+1 therefore 6y+2y+2=6 therefore 8y=4 y=0.5 sub in to either equation x=(3/2)^0.5

TF
Answered by Thomas F. Maths tutor
2705 Views

Differentiate 3x^2+1/x and find the x coordinate of the stationary point of the curve of y=3x^2+1/x

To differentiate we multiply by the power and take one off the power. d/dx(3x^2+1/x)= 6x-1/x^2 At a stationary point the gradient equals zero 6x-1/x^2=0 which rearranges to x=(1/6)^(1/3)

RW
Answered by Rachel W. Maths tutor
4061 Views

Let Sn be the sum of the first n terms of the arithmetic series 2 + 4 + 6 + ... i) Find S4

Firstly look for key terms in the question, identifying that we are going to be finding the sum of n terms, and it is an arithmetic series. This allows us to know which e...

SL
Answered by Sydney L. Maths tutor
5779 Views

Find the location of the turning point of the following curve, y = x^2 + 6x - 7

Turning point is when dy/dx = 0

if y= x2 + 6x - 7

dy/dx = 2x + 6

at turning point: 2x + 6 = 0

therefore: 2x = - 6

x coordinate: x = - 3

substitute into...

HM
Answered by Hugo M. Maths tutor
5506 Views

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