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Using the method of binomial expansion (which I will cover in more detail) we get

(2x-3y)^4 = + 1(2x)^4(3y)^0  -  4(2x)^3(3y)^1  +  6(2x)^2(3y)^2  -  4(2x)^1(3y)^3  +  1(2x)^0(3y)^4  =

= 16x...

5x - 2 > 3x + 11
5x - 3x > 11 + 2 
2x > 13
x > 13/2 
x > 6.5

First list what the question gives you. 

p=36    r=3      t=-2

Sub in the values that you know into the equation.

Q= 36/ 3(4--2)

Q= 36/18

Q=2

dy/dx = 6x² + 4x + 9

dy = (6x² + 4x + 9) dx 

integrating gives:

y= (6x³/3) + (4x²/2) + 9x + c

y= 2x³ + 2x² + 9...

6x^2 + 5x +7 =y

dy/dx = 12x + 5 

To solve for a point of inflection:

dy/dx = 12x + 5 = 0

x=-5/12

y=143/24