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y=x^2, find dy/dx

y=x^2

if y = a*x^b

then dy/dx = ba*x^(b-1)

therefore

dy/dx = 2*x

Answered by Matthew W. • Maths tutor

2822 Views

Simplify (x + 3)(2x + 5) - (x - 1)

Start by expanding the brackets: 2x^2 + 5x + 6x + 15 = 2x^2 +11x + 15 Combine the two parts of the equation: 2x^2 + 11x + 15 - x + 2 = 2x^2 + 10x + 17

Answered by Hannah M. • Maths tutor

4264 Views

Fully simplify: (y^2 x y^5) / y^3

(y²x y⁵) / y³ When multiplying, the indices must be added together, therefore y² x y⁵ = y²⁺⁵ = y⁷ (y²x y⁵

Answered by Jemima P. • Maths tutor

5111 Views

If £160 = 100%, the number we are trying to find (let's call this X) equals 145%. (Place numbers in 2x2 grid) 100% £160 145% X Multiply the two diagonal numbers together, then divide by the number ...

Answered by Jemima P. • Maths tutor

4274 Views

Describe the 3 types of solution to a quadratic equation

The behaviour of the solution depends on the value of the discriminant, D = b² – 4ac, (aptly named as it allows you to discriminate between solutions)
...

Answered by George L. • Maths tutor

3467 Views