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How to find the stationary point of y= x^2-108x^(1/2)+16 and determine the nature of the stationary point?

a). Find stationary point: Stationary point is the point at which the gradient equals zero. So first we must find the gradient and the set it to zero and solve: dy/dx= 2x-54x^(-1/2); now we set this to ze...

DS
Answered by Dylan S. Maths tutor
5225 Views

How do you multiply an "number" with powers for example a^3 * a^6

When multiplying powers: we add the powers together (3+6) so we get a^9 When dividing powers: we subtract the powers so a^6/a^3 =(6-3)= a^3 When adding or subtracting them we do not change the power. We m...

BS
Answered by Bryony S. Maths tutor
4054 Views

y=6x+2 Find the gradient of the line and the y intersect

y=mx+c where m = gradient and c = the y-intersect hence gradient= 6 and y-intersect=2

HB
Answered by Hugh B. Maths tutor
4211 Views

y= 6x + 2, Find the gradient of the line and the y-intersect

y=mx+c where m is the gradient and c is the y-intersect hence gradient=6 and y-intersect = 2 . this can also be found by differentiating the equations dy/dx = 6 and setting x=0 to find the y value.

HB
Answered by Hugh B. Maths tutor
9174 Views

If x^2 = 16, why isn't the answer just x = 4?

You're right that x = 4 is a solution to the equation - but the problem is it's not the only solution, x = -4 also works.You have to be careful not to take a shortcut by simply taking the square root of b...

LD
Answered by Laurie D. Maths tutor
15891 Views

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