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Integrate ln(x)/(x^3)

Using integration by parts split it into v'=(1/x^3) and u=ln(x). v=-1/2x^2 and u'=1/x. Integral ln(x)/(x^3) = u*v - Integral u'*v = -ln(x)*1/2x^2 - 1/4x^2 + c

AA
Answered by Archie A. Maths tutor
5047 Views

Find the integral of (x+4)/x(2-x) .dx

In order to integrate the expression we must first rewrite it in terms of Partial Fractions i.e. A/x and B/(2-x), so that when multiplied together we have a fraction with same denominator as the expressio...

AT
Answered by Aaron T. Maths tutor
4183 Views

Solve the simultaneous equations: y=x/2 + 2 and 2y+3x=12

Label the equations (1): y=x/2 + 2 and (2): 2y+3x=12. Firstly, multiply equation (1)by 2, this will give you (1a): 2y=x+4, then, substitute (1a) into (2). This gives you (x+4)+3x=12. Therefore, 4x+4=12. 4...

JB
Answered by Joseph B. Maths tutor
6049 Views

Solve the equation x^2-9x+20=0

First, we need to factorise the equation on the left hand side, this can be done by finding two numbers that add together to make the 'b' coefficient (-9) and multiply to make the 'c' coefficient (20).

JB
Answered by Joseph B. Maths tutor
29300 Views

If f'(x)=3x(x - 1), find f(x)

Due to notation difficulties, S = integral sign. This is a straightforward integration question, firstly we expand the brackets:

f'(x)=3x^2 - 3x f(x)=S(3x^2 - 3x)dx f(x)=3/3x^3 - 3/2x^2 + C f(x)=x^...

GR
Answered by Grace R. Maths tutor
4994 Views

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