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Let f(x)=x^2-ax+a-1 and g(x)=x-5. The graphs of f and g intersect at one distinct point. Find the possible values of a.

If the two graphs intersect, it means that they will share the same y and x coordinates at one particular point. (I will draw diagram to show point).

Therefore, you can set f(x)=g(x) so that x^2 -...

AO
Answered by Andres O. Maths tutor
7800 Views

x^2 - 10x + 21 = 0

  • First, factorise the quadratic equation.
  • Find two numbers that multiply to give 21 and add to give 10. 7 and 3
  • (x-7)(x-3)=0
  • Now find the value x so that when these bracket...
BS
Answered by Ben S. Maths tutor
4478 Views

Find the derivative of f(x)=x^2*e^x+x

You can split the derivative into 2 parts: dx/dy (x^2*e^x) + dx/dy (x)

For the first part you have to use the product rule, so let U=x^2 V=e^x U'=2x V'=Chain rule

V'=dx/dy(e^x)dx/dy(x)...

BR
Answered by Benedict R. Maths tutor
3745 Views

We have the curve f(x) = (x^2-5x)(x-1)+ 3x. Sketch the graph y=f(x), making sure to plot the co-ordinates where the curve meets the axes.

The first thing we want to do is re-write the curve f(x) in a format in which we can read and easily plot a graph. If we can include the '3x' in the factorised part of the equation, it will be neater and ...

RA
Answered by Rania A. Maths tutor
3394 Views

Find the gradient of y=6x^3+2x^2 at (1,1)

In order to find the gradient of the curve at (1,1), we must first differentiate the equation of the curve. To do this, multiply the coefficient of x by the power of that same x. Then subtract one from th...

BB
Answered by Ben B. Maths tutor
5234 Views

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