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Starting with the initial integral of int(exp(x).cos(x))dx we can see that this is going to have to be integrated by parts. This states that the integral of (u . dv/dx)dx is equal to u.v - int(v . du/d...
To find the gradient of any curve, we take the derivative. So in this case, we need to take dy/dx. We do this by multiplying the term by the power on x, and then lowering the power by one. For example, fo...
Let u = x and dv/dx = sin(x),
By using the general expression of:
integral(u multiply dv/dx)dx = [u multiply v] - integral(v multiply du/dx)dx, and by realising that:
All we do here is break down into three parts: x2, 6x & 1.x2 becomes 2x as we multiply by the power and then decrease the power by one.6x becomes 6 and 1 becomes 0.So alltogether...
first notice the integral is in the form f'(x)/f(x), and indefinite integrals of this form are ln|f(x)|+c. therefore the integral is [ln|x4+x|] between limits 1 and 2. subbing in li...
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