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F'(x)=3x^2+4x-5
F(x)=(3/(2+1))(x^(2+1))+(4/(1+1)) (x^(1+1))-5(x^(0+1))

Answer: F(x)=x^3+2x^2-5x+c

P(WW) = 5/8 x 4/7 = 20/56

P(BB) = 3/8 x 2/7 = 6/56

P(same colour) = 20/56 + 6/56 = 26/56 = 13/28 (simplified)

AB = 4DB

AC = 2DB

Find BC using Pythagoras:

BC = √(4DB)² + (2DB)²

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Step 1: 7k-21=3k-5

Step 2: 4k=16

Step 3: k=4

3x² +4x-12=0

Step 1: formula (-b+/- square root (b²-4ac))/2a

Step 2: a=3 b=4 c=-12

Step 3: type into your calculator 

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