Search our library of Maths questions

Top answers

Maths

All levels

Given that: y = 3x^2 + 6x^1/3 + (2x^3 - 7)/(3x^1/2), x > 0 Find dy/dx, give each term in its simplest form

y = 3x² + 6x^1/3 + (2x³/3 - 7/3)x^-1/2Using the multiplication rule for indices y = 3x² + 6x^1/3 + (2/3)x^5/2 - (7/3)x^-1/2

Answered by • Maths tutor

6522 Views

a circle c has the equation x^2 + y^2 -4x + 10y = k. find the center of te circle

you would first change the equaton into the circle equation therefore completing the square (x -2)^2 -4 + (y + 5)^2 -25 = know use the equation to deduce the center of the circle (x -2)^2 + (y + 5)^2 = ...

Answered by • Maths tutor

8586 Views

a curve has an equation: y = x^2 - 2x - 24x^0.5 x>0 find dy/dx and d^2y/dx^2

dy/dx = 2x -2 - 12x^-0.5d^2/dx^2 = 2 + 6 x^-3/2

Answered by • Maths tutor

3237 Views

Solve (x-1)^2-2(x-1)-3=0

Solving this equation would mean finding the values of x that satisfy it equating to zero. Therefore, to start, you must simplify the equation by expanding all the values to get (x^2-2x+1)-(2x-2)-3=0 [exp...

Answered by Emily L. • Maths tutor

4070 Views

Solve the equation x^6 + 26x^3 − 27 = 0

While this equation may look complicated, it's actually much easier than it looks - this equation is called a hidden quadratic. This is because it can be rewritten and solved the same way you would solve ...

Answered by Saachi P. • Maths tutor

5598 Views