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you would first change the equaton into the circle equation therefore completing the square (x -2)^2 -4 + (y + 5)^2 -25 = know use the equation to deduce the center of the circle (x -2)^2 + (y + 5)^2 = ...

dy/dx = 2x -2 - 12x^-0.5d^2/dx^2 = 2 + 6 x^-3/2

Solving this equation would mean finding the values of x that satisfy it equating to zero. Therefore, to start, you must simplify the equation by expanding all the values to get (x^2-2x+1)-(2x-2)-3=0 [exp...

While this equation may look complicated, it's actually much easier than it looks - this equation is called a hidden quadratic. This is because it can be rewritten and solved the same way you would solve ...

Step 1 Use Implicit differentiation with respect to x and y - 6x^2+3y + 3x(dy/dx) - 2/y^2(dy/dx) = 0Step 2 Write the equation as dy/dx =... - dy/dx = (6x^2 + 3y)/(2/y^2 - 3x)Step 3 Input (1,-1) into th...