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(5-x)/2=2x-7 5-x=4x-14 5=5x-14 19=5x x=19/5
consider the discriminant b2-4ac 82-4x1x17 64-68=-4 discriminant is below 0, there are no real roots therefore x2 - 8x +17 <0
f’(x)= 9x^3+4x
First we should find the gradient of the line perpendicular to PQ by rearranging the equation.5x+3y=113y=11-5xy=11/5 -5/3xy= -5/3x + 11gradient is -5/3.We know that the gradients of perpendicular lines mu...
Stationary points occur when f'(x) = 0. To find this, we differentiate f(x) to get f'(x) = 12x^3 - 24x^2. We know that at the stationary points are when f'(x) = 0. so we know that 12x^3 - 24x^2 = 0. We ca...
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