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Solve the following simultaneous equations. x^2 + 2y = 9, y = x + 3

x^2 + 2y = 9y = x + 3
x^2 + 2y = 9x^2 + 2(x+3) = 9x^2 + 2x + 6 = 9x^2 + 2x - 3 = 0(x + 3)(x - 1) = 0x= -3, x = 1
when x = -3y = x + 3y = (-3) + 3y = 0
when x = 1y = x + 3y = (1) + 3y = 4

JF
Answered by John F. Maths tutor
2529 Views

Prove that the square of an odd number is always one more than a multiple of 4

If we say n is any number, then we know 2n represents an even number - any number multiplied by 2 is always even. 2n+1 represents an odd...

RR
Answered by Rebecca R. Maths tutor
2896 Views

Simply fully (3x^2 - 8x - 3) / 2x^2 - 6x

(3x2 - 8x - 3) / 2x2 - 6x == (3x + 1)(x - 3) / 2x2 - 6x == (3x + 1)(x - 3) / 2x(x-3) == 3x+1 / 2x

GR
Answered by Gabriel R. Maths tutor
3051 Views

Solve (5− x)/2 = 2x – 7

(5-x)/2=2x-7 5-x=4x-14 5=5x-14 19=5x x=19/5

AP
Answered by Abigail P. Maths tutor
8162 Views

Show that x^2 - 8x +17 <0 for all real values of x

consider the discriminant b2-4ac 82-4x1x17 64-68=-4 discriminant is below 0, there are no real roots therefore x2 - 8x +17 <0

Answered by Maths tutor
14162 Views

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