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Maths
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The point P has coordinates (4, 5). The point Q has coordinates (a, b). A line perpendicular to PQ is given by the equation 5x+3y=11. Find an expression for b in terms of a.

First we should find the gradient of the line perpendicular to PQ by rearranging the equation.5x+3y=113y=11-5xy=11/5 -5/3xy= -5/3x + 11gradient is -5/3.We know that the gradients of perpendicular lines mu...

SB
Answered by Staś B. • Maths tutor
4265 Views

Let f(x) = 3x^4 - 8x^3 - 3. Find the x- values of the stationary points of this function.

Stationary points occur when f'(x) = 0. To find this, we differentiate f(x) to get f'(x) = 12x^3 - 24x^2. We know that at the stationary points are when f'(x) = 0. so we know that 12x^3 - 24x^2 = 0. We ca...

YS
Answered by Yathavan S. • Maths tutor
3076 Views

Celine has £5 to buy pens and rubbers. Pens are 18p each. Rubbers are 30p each. She says “I will buy 15 pens. Then I will buy as many rubbers as possible. With my change I will buy more pens.” How many pens and how many rubbers does she buy? [5 marks]

Answer: 16 pens and 7 rubbers

AR
Answered by Ardra R. • Maths tutor
2726 Views

x^2 = 4(x – 3)^2

This is a quadratic equation, which contains terms up to x2. All quadratic equations can be written in the form ax2 + bx + c = 0 where a, b

JW
Answered by Jennifer W. • Maths tutor
3341 Views

Solve 10(x + 2) – (2x – 9) = 30

10(x+2) -(2x-9)=30; 10x+20-2x+9=30 paying attention to the sign change when solving the brackets; 8x+29=30; 8x=1 separating in order to find out x; x=1/8

CE
Answered by Cristian E. • Maths tutor
4428 Views

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