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We need to split the initial fraction into two. We know that (x-5)/(x+1)(x-2) is equivalent to A/(x+1) + B/(x-2). Multiplying by (x+1)(x-2) we get x-5 = A(x-2) + B(x+1). Expanding the brackets gives x - 5...

The unknowns in a simultaneous equation need to be solved, which in this case are x and y.The method I will be using is by elimination:First, find which unknown has the same coefficient. In this example t...

This is a classic "picture frame" resolving forces question. By resolving horizontally we can use the "assuming the particle remains stationary" meaning the forces must cancel...

Firstly, we need to make the unknown variable(p) the subject of the formula. As this is the denominator of a fraction we can multiply both sides of the equation to get rid of the denominator on the right ...

First, we're going to split this 1 fraction into 2 fractions. Let (x+2)/((x+5)(x-7)) = A/(x+5) + B/(x-7) then multiplying by (x+5)(x-7) gives A(x - 7) + B(x + 5) = x + 2 multiplying this out we achieve Ax...