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The equation is in the form ax^2 + bx + c, where a = 1, b = 10 and c = 2To complete the square, we write (x + b/2a)^2 + c - (b/2a)^2So here we would have (x + 5)^2 + 2 - 25Therefore completed square form ...

a) We factorise to find 2 numbers a and b in (x + a)(x + b) such that a + b = -3 and whose product is -10 (ab = -10). (x + 2)(x - 5) = 0 -> x = 5 or -2b) This is a direct application of the quadratic f...

This problem is best split into two parts either side of the '+' sign seen as they are independent of each other, so the first part: 3(2a+2), as the 3 is outside of the bracket we have to multiply everyth...

First of all let's give some examples: 5^2=4x6+1 = 25 or 6^2 = 5x7+1 = 36. To prove it for every number let's call the number x (e.g. x was 5 and 6 in the cases above). Then the result we want to prove is...

Firstly, we know that it is an isosceles triangle, meaning that 2 of its sides are equal. In this case, the uneven side is given as x+4, so we can assume that the triangle has 3 sides: AB= X+3BC= X+3AC= X...