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g = b+8g+b = p = 2b+1(b/p) x (b-1)/(p-1) = 1/5(b^2 - b)/(p^2 - p) = 1/5sub in p= 2b+1(b^2 - b)/(4b^2 + 2b) = 1/55b^2 - 5b = 4b^2 + 2bb^2 -7b = 0b = 7 or b = 0 (cannot be 0 as 2 pens must be taken)p = 2(7)...

1/27 (1/3 x 1/3 x 1/3)

5 and 2/3

In order for the passenger to feel weightless, they must have a vertical acceleration equal to the acceleration due to gravity, i.e. they must be accelerating downward at a rate of 9.81m/s². ac...

First we form equations from the information given in the question. The first equation we can form is that d is directly proportional to the square of t. This means that d = kt² ,where k is a ...