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f'(x)=3cos3x-3differentiating the sin3xchain ruley =sinu u=3xdy/du=cosu du/dx=3dy/du x du/dx = 3cosuu= 3x3cos3x - 3

Quotient Rule:d(u/v)/dx = (vu' - uv')/(v²)u = sin(2x) => u' = 2cos(2x)v = x² => v' = 2x=> (2x²cos(2x) - 2xsin(2x))/(x⁴)Product Rule:d(uv)/dx = vu' + uv...

First, we need to define what an odd number is. An odd number can be expressed as the product of 2n+1, where n can be any whole number bigger than 0. You can check this by inputting a few numbers for n (s...

9x>27X>3

We can rewrite the function to eliminate the annoying 1/x^2 expression by knowing this can also be expressed by x^-2.f(x) = 6x^-2 + 2xNow we can differentiate this function term by term, first 6x^-2. We k...