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The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle.

3+4+5=12
72/12=6
36= 18 46=24 56=30
Area of a right-angled triangle= a
b/2
18240.5= 216

SK
Answered by Saif K. Maths tutor
2602 Views

Demonstrate that (2^n)-1 is not a perfect square for any n>2, n ∈ N.

Assumption: If sqrt(2^n- 1) ∈ℕ , it means that there is a k ∈ ℕ such that (2^n-1) = k^2  ⇒ k is odd, so there is m ∈ ℕ such that (2^n-1)=(2m+1)^2 . By solving the equation we get 2^n= 4m^2+4m+2. We divide...

IV
6904 Views

Differentiate the equation: 3x^2 + 4x + 3

3x2 + 4x + 3 = 6x + 4

KA
Answered by Kasam A. Maths tutor
1377 Views

Prove that the square of an odd number is always 1 more than a multiple of 4

An odd number can be expressed by the formula "2n + 1" where n stands for any integer. Therefore, the square of any odd number can be expressed as:(2n+1)^2 = (2n+1)(2n+1) = 4n^2 + 4n + 1 = 4(n^2...

EB
Answered by Edward B. Maths tutor
3138 Views

Solve the simultaneous equation x+y=11(1), x^2+y^2=61 (2)

Make x the subject in the equation x+y=11(1). This will help us eliminate x in the second equation (2).x=11-y (3)Substitute (3) into (2)(11-y)2+y2=61Expanding the brackets and simpli...

Answered by Maths tutor
3893 Views

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