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There are three steps to solving these types of straight line problems. 1) Find the gradient (slope) of the line. 2) Find the point slope formula. 3) Solve for y.1) The gradient (m) of the line bet...
Firstly, a stationary point is a point on the curve where the gradient of the tangent line is equal to 0. Here, this occurs at points where the first derivative of f(x) = 1/3xOMAnswered by Omar M. • Maths tutor6964 Views
This is a typical example of a 3 mark question on a GCSE higher paper. The first mark would be awarded for multiplying both sides of the equation by 2, and then expanding the brackets:10 - x =2(2x-6)10 - ...
For y = f(x)+4: the graph undergoes a translation of (0,4) For y = f(x-5): the graph undergoes a translation of (5,0) For y = -f(x+4): the graph is reflected w.r.t the x-axis and translated by (-4,0)*imag...
The ways to complete the first one is to realise that it involves a difference of two squares. If you were to see (X^2) with a constant (number), you know they have no factor in common, meaning the two te...
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