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n is an integer such that 3n + 2 < 14 and 6n/(n^2+5) > 1. Find all possible values of n.

First of all, solving the equation 3n + 2 < 14 to find n. 3n < 14 -2 = 3n < 12. n < 12/3 = n < 4Secondly solve the equation 6n/(n^2+5) > 1 to find n. Collect all terms on one side of the...

Answered by Kai P. • Maths tutor

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Split (3x-4)/(x+2)(x-3) into partial fractions

(3x-4)/(x+2)(x-3) = A/(x+2) + B/(x-3)=> 3x-4 = A(x-3) + B(x+2)Let x = -2-10 = -5AA = 2Let x = 35 = 5BB = 1∴ (3x-4)/(x+2)(x-3) = 2/(x+2) + 1/(x-3)

Answered by • Maths tutor

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Solve the quadratic equation (x^2)-x-12=0 (easy), (x^2)-9=0 (special case), (x^2)+5x-13=0 (quadratic formula)

For each of the above the methodology is fairly similar, first try and do it just by looking at it then try the quadratic formula if that doesn't work. At GCSE level I don't think there's any need to worr...

Answered by Jack E. • Maths tutor

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Maths A Level: "Sketch the curve of the function f(x) = 2x^3 - 2x - 12 and show that the equation f(x)=0 has one root; calculate the root."

Consider the curve y = 2x^3 - 2x - 12.1) y-intercept. When x=0, y= -12 3) when x tends to infinity...y tends to infinity and when x tends to negative infinity...y tends to negative infinity 4) stationary ...

Answered by Joseph I. • Maths tutor

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Prove that the square of an odd number is always 1 more than a multiple of 4

(2x-1)² = 4x²- 4x + 1= 4(x²-x)+1The part of the expression which is: 4(x²-x) indicates that the value is a multiple of 4. The number 1 is then added which means...

Answered by Gokul P. • Maths tutor

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