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We know the values for the 2nd and 5th terms and already have the 2nd term as an equation but not the 5th. Therefore, we need to start by working out what exactly the 5th term is in terms of a and b. From...

To solve a quadratic equation of the form Ax² + Bx + C = 0, where, in this example, A=1, B=7 and C=6, we need to factorise the left-hand side of the equation. To do this we first need to write ...

We know that A+B = 8 so we should first count the number of ways that the two dice could total 8. (A = 2, B = 6), (A=3, B=5), (A=4, B=4), (A=5, B=3) , (A=6, B= 2) -- this gives 5 possible waysWe also know...

To answer the question the equation given must be rearranged into the straight line formula, y=mx+c, where m is the gradient of the slopeminus 4x from both sides, we now have 3y=12-4xthen divide through...

-4<x<2Work out using whiteboard