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To solve a quadratic equation of the form Ax² + Bx + C = 0, where, in this example, A=1, B=7 and C=6, we need to factorise the left-hand side of the equation. To do this we first need to write ...

We know that A+B = 8 so we should first count the number of ways that the two dice could total 8. (A = 2, B = 6), (A=3, B=5), (A=4, B=4), (A=5, B=3) , (A=6, B= 2) -- this gives 5 possible waysWe also know...

To answer the question the equation given must be rearranged into the straight line formula, y=mx+c, where m is the gradient of the slopeminus 4x from both sides, we now have 3y=12-4xthen divide through...

-4<x<2Work out using whiteboard

The easiest way to solve these equations is by substitution. Rearrange the 6y=-x+64 equation into the form of x=64-6y. Replace x in the other equation with x=64-6y to produce y+5(64-6y)=30. Multiply out t...