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In a right angle triangle (where angle ABC is 90 degrees), you are given that angle /_ ACB is 14 degrees and length "AB" is 4. Find the length of "BC".

Using SOH CAH TOA, and labelling each side of the triangle, we see that we are using "TOA". We have the following: tan(14)=4/"BC". Rearranging for "BC", we get the following:...

AW
Answered by Andreas W. Maths tutor
2610 Views

Factorise the following- A) 4x+12xz. B) 3xy + 6y d) 4A^2B^2+ 8AB^2 +16AB^3

A) Firstly look at what is common - X and the number 4. Take these out the bracket . Then think what you have left and place that in the inner bracket. 4x(1+3z)
B) Again this is similar to the first ...

HC
Answered by Hannah C. Maths tutor
2442 Views

When do two simultaneous equations have a solution?

This question was put to someone during their teacher training. This is a good question to ask, it is very important in maths to know that something you intend to study does actually exist. To explain the...

DD
Answered by Dylan D. Maths tutor
2610 Views

8^(3/4)*2^(x) = 16^(4/5). Work out the exact value of x.

8 = 2^3 and 16 = 2^4. Substituting these into the above equation, we get 2^(9/4)*2^(x) = 2^(16/5). Using the laws of indices, we can derive the equation (9/4) + x = (16/5). In decimal form, this is 2.25 +...

KS
Answered by Katherine S. Maths tutor
5445 Views

Make x the subject of the formula 4(2x-y) = 3ax - 5

4(2x-y) = 3ax - 5Step 1 - Expand 8x - 4y = 3ax - 5Step 2 - Collect like terms 8x - 3ax = 4y - 5Step 3 - Factorise x(8-3a) = 4y - 5Step 4 - Isolate x x = (4y - 5)/(8-3a)

AS
Answered by Adam S. Maths tutor
2861 Views

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