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The equation 5x sqaured + px + q , where p and q are constants, has roots α and α + 4. (a) Show that p squared = 20q +400.

a+a+4 = -p/5a+2 = -p/10(a+2)sqaured = q/5 +4p sqaured/100 = q/5 +4p sqaured = 100(q/5 +4)implies p squared = 20q+400

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Factorise (x^2-100) and then solve for x.

When looking at factorising quadratic equations, the first approach should be to identify what is in front of the x term and the value of the c term, with the equation being in the form of y=A(x^2)+Bx+c.S...

Answered by Syed A. • Maths tutor

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Solve x/2 + 3x/(x+) = 1

(x/2) + 3x/(x+1) = 1x(x+1) + 6x = 2x + 2x² + x + 6x - 2x = 2x² + 5x - 2 = 0
Using the quadratic formula,
x₁ = (-5+(29)^1/2)/2x₂ = (-5-(29)

Answered by Emily D. • Maths tutor

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Show that a parallelogram is composed of an isosceles trapezium and an isosceles triangle

Draw a parallelogram composed of a trapezium and a traingle.Label:obtuse trapezium anlges as aacute trapezium angles as bbase triangular angles as ctop triangular angle as d
By definition of a parall...

Answered by Emily D. • Maths tutor

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