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Rectangle ABCD has sides 2x+5 and x+2 with rectangle EFGH of sides x+3 and x cut out of it. The total area of shape ABCD is 5cm^2. Show that 0 = x^2 + 6x +5 [5 Marks]

Area of ABCD = (2x+5)(x+2) = 2x² +9x +10Area of EFGH = (x+3)(x) = x² + 3xTotal Area = 5 = ABCD - EFGH = 2x² +9x +10 - x² - 3x 5 = x² + 6x +10 0 = x

Answered by Arad S. • Maths tutor

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Once upon a time, in the Ancient Wizarding World of Haberdasher’sOne pound = 20 shillings One shilling = 12 penceA large Margarine-beer costs 1 pound 4 shillings and 9 pence. A small Margarine-beer costs ...

Answered by Darren P. • Maths tutor

3144 Views

What is 18⁄4 as a mixed fraction in its simplest form?

DIVIDE 18 BY 4 USING BUS STOP METHOD TO GET 4 WITH 2 LEFT OVERTHEREFORE BECOMES 4 AND 2/4THEN SIMPLIFY TO 4 1/2

Answered by Adeel A. • Maths tutor

3695 Views

A curve is defined by the equation y^2 - xy + 3x^2 - 5 = 0. Find dy/dx.

2y dy/dx - x dy/dx - y + 6x = 0dy/dx (2y-x)= y-6xdy/dx= (y-6x)/(2y-x)

Answered by Witold A. • Maths tutor

5053 Views

Given that y={(x^2+4)(x−3)}/2x, find dy/dx in its simplest form.

Looking at the problem to start we can see that this is an algebraic division problemThere are three common methods you will come across for finding dy/dx for algebraic problems: The Chain Rule, The Produ...

Answered by Meeza T. • Maths tutor

7128 Views