Rectangle ABCD has sides 2x+5 and x+2 with rectangle EFGH of sides x+3 and x cut out of it. The total area of shape ABCD is 5cm^2. Show that 0 = x^2 + 6x +5 [5 Marks]

Area of ABCD = (2x+5)(x+2) = 2x2 +9x +10Area of EFGH = (x+3)(x) = x2 + 3xTotal Area = 5 = ABCD - EFGH = 2x2 +9x +10 - x2 - 3x 5 = x2 + 6x +10 0 = x2 + 6x +5(Follow up question could be to find x, either by factorising above equation or using the quadratic formula)

AS
Answered by Arad S. Maths tutor

2790 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 5x+y=21, x-3y=9


Solve the two simultaneous equations X2 +2Y2= 18 and X - Y = 3


How do you use the quadratic formula?


Express 56 as a product of its prime factors


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences