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Consider three simple functions F(x)=2x, G(x)=2x-6, H(x)=2x + π/2. We can differentiate these functions with respect to x to get F’(x)=f(x)=2, G’(x)=g(x)=2, H’(x)=h(x)=2. Clearly the derivatives of these ...

X coordinates = (-3+1)/2 = (-2)/2 = -1Y coordinates = (-3+3)/2 = (0) /2 = 0 Coordinates of the midpoint = (x,y) = (-1,0)
If they were struggling to visualise it/to avoid simple mist...

h² = 25So firstly, we must square root each side of the equation.(square root) h² = (square root)25.so... h= (square root)25.h=5. or h=-5.

(6x^2+4x-15x-10)(x+7)(6x^2 -11x-10)(x+7)= 6x^3-11x^2-10x+42x^2-77x-70)=6x^3+31x^2-87x-70

Let A by any 2 by 2 matrix and the top left, top right, bottom left and bottom right entries be a, b, c and d respectively. The determinant for matrix A would be ad-bc.