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Find the tangent to the curve y = x^2 + 3x + 2 that passes through the point (-1,0), sketch the curve and the tangent.

Differentiate to find dy/dx = 3x + 2;at point (-1,0) dy/dx = -1substitute in to y = mx + c, noting m = -1 and the line passes through (-1,0) yields c = -1y = -x - 1, simple to sketch this line.curve sketc...

PW
Answered by Peter W. Maths tutor
2847 Views

How do I find roots of a quadratic equation when I can't factorise?

When factorising isn't working, we can try using the quadratic formula. First, we need our quadratic equation and find a,b and c - the coefficients of x and the constant. Now, we can wri...

FD
Answered by Freya D. Maths tutor
3390 Views

It is given that sin(x) = 1/2. Find the value of sec(x)

x = 30ºcos(30) = √3/2sec(30) = 2/√3 or 2√3/3

AH
Answered by Alex H. Maths tutor
2595 Views

Show that cosh(x+y) = cosh(x)cosh(y) + sinh(x)sinh(y)

RHS: cosh(x)cosh(y) + sinh(x)sinh(y) = 1/4(e^x + e^-x)(e^y + e^-y) + 1/4(e^x - e^-x)(e^y - e^-y) = 1/4(e^x.e^y + e^x.e^-y + e^-x.e^y + e^-x.e^-y + e^x.e^y - e^x.e^-y - e^-x.e^y + e^-x.e^-y) = 1/4(2e^x.e^y...

AH
Answered by Alex H. Maths tutor
5582 Views

A curve has equation y = (12x^1/2)-x^3/2

y = 12x1/2 - x3/2
First take the 1/2 power and multiply by the integer in front of the x (so 12 x 1/2 = 6), then minus 1 from the power (1/2 - 1 = -1/2) and replace the power ab...

AB
Answered by Amay B. Maths tutor
5193 Views

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