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y = 2 (-1)2 -5(-1) -1y = 2 + 10 - 1y = 11y = 2 (2)2 -5(2) -1y = 8 - 10 -1y = -3
Step 1: Differentiate the equation Y = X^3 + X + 6 to find the gradient of the line at any point. To do this, multiply each term of X by the old power and -1 from that power. This makes dy/dx = 3X^2 + 1.S...
Rearrange both equations so that both are in the form y= something. Move the x terms to the right of both equations. y=5x+2 6y=30x+36 Factorise second equation so that common factor of 6 is shown...
1/(x(a-x)) = B(1/x + 1/(a-x)) Note: the '≡' sign (defined equivalence) can be used in place of '=' but this is not necessary to achieve full marks.Step: multiply both sides by x(a-x)1 = (x(a-x))B(1/x + 1/...
2x2+4x+6x+12=2x2+10x+12
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