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Answer: 4x3 + 12x2y + 9xy2 - 16x2 - 48xy - 36y2
(1) y-3x+2=0(2) y2-x-6x2=0Using (1): y=3x-2Sub y value into (2): (3x-2)2-x-6x2=0Expand the brackets: 9x2-13x+4-x-6xPAAnswered by Phoebe A. • Maths tutor7668 Views
cos(4x) = cos(2(2x)) = 2(cos^2(2x)) - 1 = 2 (cos^2(x) - 1)^2 - 1 = 8(cos^4(x)) - 8(cos^2(x)) + 1
Firstly, increase the power outside the brackets by 1 and divide the whole thing by the new power. This gives 3/4(4x+1)4/3Next, divide the whole thing by the derivative of the bracket. The deri...
x2 -x -12 = 0. Here we have rearranged the equation so that we have 0 on one side of the equation, allowing us to now factorise. (x - ...
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