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Firstly, differentiate the equation to find dy/dx.
dy/dx = 20 - 2x - 6x²
As dy/dx represents the gradient, we know that for a stationary point the gradient must be zero, hence for the...

lets expand the first two brackets first, so x * x gives x², x * 2 gives 2x, x * 1 gives x and 1 * 2 = 2. 2x and x are both in terms of x so we add these together to get 3x, giving us the quadr...

f(1) = 31^3 + 21^2 - 7*1 + 2 = 3 + 2 - 7 + 2 = 0

The rule for simplifying indices is to take them one at a time, so separate the problem into 16^(1/2)^3, which is 4^3, which is 64.

A stationary point on a curve is when the differential of the equation of the curve = 0. In other words when dy/dx = 0Take the equation in the question: y = 20x - x² - 2x³A simple ru...