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Differentiate the equation.Let the derivative equal to 0 and get x.Substitute the value of x into the original equation to get y.
a) 54-45+3a+18=0 3a+27=0 3a=-27 and thus a=-9b) 2x^3 – 5x^2 -9x + 18 = (x-3) (2x^2 +bx-6)to find b ; collect the x^2 terms so bx^2-6x^2=-5x^2 and thus b=1c) when comparing f(y) and f(x) we see ...
ex^2 --------> dy/dx = 2xex^2
Consider the equation x^2+5x+6=0. In order to factorise this equation you first need to think of what numbers sum to make 5 (the coefficient of x) and whose product equals 6 (the number not multiplied by ...
First we need to get everything that is not x on to one side. This will then leave us with 4x=3g- 8s-9t. Now we need to remove the coefficient of x which will result in x=1/4(3g-8s-9t)- as we have x on it...
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