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A curve has equation y = 20x −x^2 −2x^3 . Find its stationary point(s).

Differentiate the equation.Let the derivative equal to 0 and get x.Substitute the value of x into the original equation to get y.

RL
Answered by Ruonan L. Maths tutor
5005 Views

f(x) = 2x3 – 5x2 + ax + 18 where a is a constant. Given that (x – 3) is a factor of f(x), (a) show that a = – 9 (2) (b) factorise f(x) completely. (4) Given that g(y) = 2(33y ) – 5(32y ) – 9(3y ) + 18 (c) find the values of y that satisfy g(y) = 0, givi

a) 54-45+3a+18=0 3a+27=0 3a=-27 and thus a=-9b) 2x^3 – 5x^2 -9x + 18 = (x-3) (2x^2 +bx-6)to find b ; collect the x^2 terms so bx^2-6x^2=-5x^2 and thus b=1c) when comparing f(y) and f(x) we see ...

AK
Answered by Akrit K. Maths tutor
8003 Views

Differentiate e^x^2

ex^2 --------> dy/dx = 2xex^2

CC
Answered by Connor C. Maths tutor
3835 Views

How do I solve quadratic equations by factorization?

Consider the equation x^2+5x+6=0. In order to factorise this equation you first need to think of what numbers sum to make 5 (the coefficient of x) and whose product equals 6 (the number not multiplied by ...

RF
Answered by Ricardo F. Maths tutor
2880 Views

Re-arrange [4x+ 9t + 8s= 3g] to make x the subject of the formula

First we need to get everything that is not x on to one side. This will then leave us with 4x=3g- 8s-9t. Now we need to remove the coefficient of x which will result in x=1/4(3g-8s-9t)- as we have x on it...

VP
Answered by Vaidik P. Maths tutor
2780 Views

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