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x2+y2=25; y-3x=13; x2+(13+3x)2=25; x2+9x2+78x+169=25; 10x2+78x+144=0; 5x2+39x+72=0; (5x+24)(x+3)=0; x=-24/5 and y=-7...
dy/dx=(dy/dt)*(dt/dx); dy/dt=3+16t-3; dx/dt=3(t-1)2; dt/dx=1/3(t-1)2; dy/dx=(3+16t-3)/3(t-1)2
x3 - 6x2 + 11x - 6 = 0Let (x-a)(x-b)(x-c) = x3 - 6x2 + 11x - 6=> abc = -6 and a + b + c = -6 From abc=-6, find the possibilities of their values: (1,2,...
Since this problem contains both xs and ys on the right hand side, we need to use implicit differentiation. This is where we use the chain rule to differentiate with regards to x the terms which contain y...
L1: y=5x-4L2: 2y-10x+16=0. Rearranged: 2y=10x-16, y=5x-8 The coefficient of x is the same in both equations when expressed in standard format (5), therefore the lines are parallel. AWAnswered by Alfie W. • Maths tutor4846 Views
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