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Solve the differential equation (1 + x^2)dy/dx = x tan(y)

Firstly rearrange the equation so that only dy/dx is on the left hand sidedy/dx = (x/(1+x^2)) tan(y)Now separate the variables such that the x terms are on one side with the dx,...

CG
Answered by Christian G. Maths tutor
6105 Views

168 is 4/7 of a number. What is the number?

If 168 is four sevenths of a number then divide this by 4 to give 1 seventh of the number.
168/4 = 42
So 42 is one seventh of the number.
Now multiply this by 7 to find the number.
42*...

WL
Answered by William L. Maths tutor
4673 Views

Find the stationary point of the curve y=3x^2-2x+2 and state the nature of this stationary point.

The stationary point is a minimum point. I will run through the working out for the question using the whiteboard in the session as it is difficult to demonstrate without relevant formatting.

WL
Answered by William L. Maths tutor
3444 Views

Differentiate the function y = (x^2)/(3x-1) with respect to x.

This requires use of the quotient rule: d/dx[f(x)/g(x)] = [g(x)f'(x) - g'(x)f(x)]/[g(x)^2]dy/dx = ([(3x-1)*2x] - 3x^2)/[(3x-1)^2],= (3x^2-2x)/[(3x-1)^2],=[x(3x-2)]/[(3x-1)^2]

TS
Answered by Ted S. Maths tutor
6562 Views

A curve has equation y = x^3 - 3x^2 -24x + 5, find the x co-ordinates of the two stationary points of the curve and hence determine whether they are maximum or minimum points.

y = x3 - 3x2 - 24x + 5, First, calculate the derivative of y and find its roots when y = 0:dy/dx = 3x2 - 6x -24 = 0 -> x2 - 2x - 8 = 0 -> (x+2)(x-4) = 0Th...

TS
Answered by Ted S. Maths tutor
7656 Views

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