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Find the stationary points of the curve f(x) =x^3 - 6x^2 + 9x + 1

Step One: stationary/turning points are points on the curve where the gradient equals 0 (i.e. a point at which the slope changes from negative to positive, or vice versa). So we ne...

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Answered by Angharad L. Maths tutor
9928 Views

Solve the following equations. Leave answers in simplest terms a)e^(3x-9)=8. b) ln(2y+5)=2+ln(4-y)

a) Using log rules, a^x=b becomes log(a)b=x. If we take ln of both sides, we get ln(e^(3x-9))=ln8. ln(e) =1, so we just get 3x-9=ln8. Now we can simply manipulate this to get x=(9+ln8)/3=3+(1/3)ln8. Anoth...

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Answered by Ben W. Maths tutor
6375 Views

a) show that (cosx)^2=8(sinx)^2-6sinx can be written as (3sinx-1)^2=2 b)Solve (cosx)^2=8(sinx)^2-6sinx

Start with a). Looking at this equation, the trig identity screaming out is cosx^2+sinx^2=1--> cosx^2=1-sinx^2. Substituting this into the LHS of the equation, and with a bit of algebraic rearrangement...

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Answered by Ben W. Maths tutor
23089 Views

Solve the following simultaneous equations. x^2+y^2=25. y-3x=13

The key to solving simultaneous equations is trying to reduce them into one equation. You can see that one of these equations is quadratic, so you should be thinking there will be 2 answers for x and y. Y...

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Answered by Ben W. Maths tutor
4814 Views

Solve these two simultaneous equations.

eq.1 4x+3y=7eq.2 3x+7y=16
You want to eliminate one of the variables (either x or y) reducing the problem to just one equation with one variable which can be solved. This can be done by multiplying e...

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Answered by Tobias H. Maths tutor
4180 Views

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