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Make x the subject of, 4(x+1)/(x+2) = y

The fundamental rule to keep in the back of your head is 'whatever happens to one side must happen to the other'. This way we can be sure that whatever is on the left hand side of the equals sign will be ...

Answered by Jack W. • Maths tutor

4430 Views

How do you find stationary points of an equation, eg. y=x^2+3x+2

Stationary points of an equation are found where the gradient of the tangent at this point equals zero. A diagram can illustrate this. To find them differentiate the given equation (which gives the gradie...

Answered by Ellie C. • Maths tutor

3187 Views

Solve the equation 3x + 1 = 4x - 2

In order to tackle this equation, we have to keep in mind that whatever we do to one side of the equation we have to do to the other. Our aim is going to be to get all of the x's together on one side of t...

Answered by Codie W. • Maths tutor

7539 Views

ABC and BCD are two attached triangles, attached along line BC. AB = 5.8cm, AC=5.2cm, BD=4.3cm. Angle BDC = 30 degrees, and angle DCB is a right angle. Calculate angle CBA.

This question teaches the importance of drawing diagrams to figure out what a question is asking, as well as deeply testing how well the student understands trigonometry and equation rearrangement, combin...

Answered by Charles S. • Maths tutor

5554 Views

Find the equation of the tangent to: y = X^2 + 3x + 2 at the point (2,12)

(1) Find the gradient using differentiation (2) If the gradient at (x₁,y₁) is m,y - y₁ = m(x - x₁)
(1) We differentiate the given equation:dy/dx = 2x + 3 <...

Answered by Samuel C. • Maths tutor

3914 Views